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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results

please answer this question

script.js
function returnValue(name){
  var echo = return name;
} 
returnValue("Mohammad");
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, mo sam ! My guess (based on your code) is that for step 1 you had this:

function returnValue(name){
  return name;
} 

The second step of the challenge starts with this:

After your newly created returnValue function, create a new variable named echo.

But your echo variable isn't after the function, it's inside it. We want to run this function and assign the value of whatever it returns to the variable echo. So to alter your code to pass (it wouldn't be by much) you could do this:

function returnValue(name){
   // name will now be equal to "Mohammed" when called
   return name;
} 

// create variable and call the function sending in "Mohammed"
// The echo variable is assigned the result "Mohammed" which is returned from the function
var echo = returnValue("Mohammad");

Hope this helps! :sparkles:

Adam Beer
Adam Beer
11,314 Points

You are near. There is a two ways. First, save the name in a variable, and finally return the value of variable, like this.

function returnValue(name){
  var echo = name;
  return echo;
} 
returnValue("Mohammad");

or Second, return the value right away, like this,

function returnValue(name){
  return name;
} 
returnValue("Mohammad");

Thanks alot

Steven Parker
Steven Parker
229,786 Points

But you'd still need to assign "echo" using the result of the function call.