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JavaScript AJAX Basics (retiring) Programming AJAX Check for the correct ready state

Posted by James Maddox
James Maddox
17,154 Points

Ajax Challenge 1 of 4

I can't get my code to pass... what am I missing or doing wrong?

// app.js
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
  if (request.readyState === 4) {
    document.getElementById("sidebar").innerHTML = request.responseText;
  }

};
xhr.open('GET', 'sidebar.html');
xhr.send();

//index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="sidebar"></div>
</body>
</html>
Harry James
Harry James
14,780 Points
Harry James
Harry James
14,780 Points

Apologies! It has been quite some time since I've worked with JavaScript and the only bit I learnt was the basics!

I appreciate you asking me to answer your question but sadly, I don't know the answer to it!

Hopefully someone will come along soon with better knowledge of JavaScript who will be able to help you out :)

Also, I have updated the formatting of your code so that it will be easier for someone else to read.

1 Answer

Jason Anello
PLUS
Jason Anello
Courses Plus Student 94,610 Points
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi James,

You're using a request variable which you haven't defined. Try using the xhr variable instead.

Also, for task 1 you should not have anything inside your if condition yet.

if (xhr.readyState === 4) {

}