JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

Russ Perry
Russ Perry
13,418 Points

AJAX Challenge Task to use .open() not working and I don't know why?

So, I am pretty sure I am right, unless I am not understanding the question? Its telling me I am wrong and that I need to use open().

var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }"GET", "footer.html");
<!DOCTYPE html>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
  <div id="main">
  <div id="footer"></div>

1 Answer

Russ Perry
Russ Perry
13,418 Points

Well now I just feel stupid. Thank you!