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JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

Russ Perry
Russ Perry
13,418 Points
Posted by Russ Perry
Russ Perry
13,418 Points

AJAX Challenge Task to use .open() not working and I don't know why?

So, I am pretty sure I am right, unless I am not understanding the question? Its telling me I am wrong and that I need to use open().

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
  request.open("GET", "footer.html");
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,968 Points

Place the code below the function

Russ Perry
Russ Perry
13,418 Points
Russ Perry
Russ Perry
13,418 Points

Well now I just feel stupid. Thank you!