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Python Python Basics (2015) Letter Game App Even or Odd Loop

Alright, last step but it's a big one.

Hello lads,can anybody help me? It seems that my code is right, but the challenge didn't accept that

even.py
import random
start = 5

while start > 0:
    rand_number = random.randint(1,99)
    start -= 1
    if even_odd(rand_number) == True:
        print("{} is even".format(rand_number))
    else:
        print("{} is odd".format(rand_number))


def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

3 Answers

Reyam Marcos
PLUS
Reyam Marcos
Courses Plus Student 10,367 Points

try this one,

import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    number = random.randint(1, 99)
    if even_odd(number):
        print("{} is even".format(number))
    else:
        print("{} is odd".format(number))
    start -= 1

hope it helps

Thomas Fildes
Thomas Fildes
16,201 Points

Hi Jirka,

I used the following code to pass this challenge:

while start:
    randomNumber = random.randint(1, 99)
    if randomNumber % 2 == 0:
        print("{} is even".format(randomNumber))
    else:
        print("{} is odd".format(randomNumber))
    start -= 1

The start variable needs to decrement by 1 after the if statement and the if statement needs to check if the number is even by using modular (%). Hope this helps! Happy Coding!!!

Okay :) thank you guys