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iOS Swift Basics (retired) Control Flow Exercise: FizzBuzz Generator

Posted by Isaac Gonzalez
Isaac Gonzalez
1,857 Points

Am I correct?

I made this code:

var number = 90

if number % 3 == 0{
    println("Fizz")
}
if number % 5 == 0{
    println("Buzz")
}

if number % 5 == 0 && number % 3 == 0{
    println("FizzBuzz")
}

but on the video shows a "1...10" value so I don't know if I read well the instructions.

2 Answers

Bradley Anderson
.a{fill-rule:evenodd;}techdegree
Bradley Anderson
Full Stack JavaScript Techdegree Student 9,030 Points

When you run this you will get:

Fizz Buzz FizzBuzz

each one of the if statements are true, so the body of them will run. The exercise only wanted one of the three to print out. The expected output is "FizzBuzz".

You need to use else if statements to make sure only one of the conditions will work.

Isaac Gonzalez
Isaac Gonzalez
1,857 Points

Thank you ^^

Nate Bird
Nate Bird
7,999 Points
Nate Bird
Nate Bird
7,999 Points

You also want to adjust the order of the if else statements. You’ll need to place the ‘FizzBuzz’ statement first or it will never be reached because the ‘Fizz’ or ‘Buzz’ will be true before it reaches the last condition.

Here is my take on your approach.

var number = 10

if number % 5 == 0 && number % 3 == 0 {
    println("FizzBuzz")
} else if number % 5 == 0 {
    println("Buzz")
} else if number % 3 == 0 {
    println("Fizz")
}
Frances Angulo
Frances Angulo
5,311 Points
Frances Angulo
Frances Angulo
5,311 Points

So I guess this is not exhaustive - I implemented an else statement. The instructions for the quiz did not say "for a given range, bring a list of fizz/buzz/fizzbuzz" so I think the solution stands! 

var number = 25

if number % 3 == 0 && number % 5 == 0 {
    println("fizzbuzz")
} else if number % 5 == 0 {
    println("buzz")
} else if number % 3 == 0 {
    println("fizz")
}
else {
    println("else")
}