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Android Build a Simple Android App with Kotlin Basic Android Programming Using the Random Class

Enyang Mercy
PLUS
Enyang Mercy
Courses Plus Student 2,339 Points
Posted by Enyang Mercy
Enyang Mercy
Courses Plus Student 2,339 Points

Android string randomNumber ERROR: 'randomNumber' should be string

Stuck for a week!!!!!!!!!!!!!!!!!!!!!!! please help urgently.

RandomTest.kt 
import java.util.Random

Random randomGenerator = new Random();

int randomNumber = randomGenerator.nextInt(10);

String intAsString = randomNumber + ""
Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points
Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points

String intAsString = String.valueOf(randomNumber);

Here :) this converts int to String and i see also at end of the line you must add semicolon ---> ;

you have write : String intAsString = randomNumber + ""
you must write : String intAsString = randomNumber + "" ;

but the better way its this with: String.valueOf(int);

:)

3 Answers

Enyang Mercy
PLUS
Enyang Mercy
Courses Plus Student 2,339 Points
Enyang Mercy
Enyang Mercy
Courses Plus Student 2,339 Points

Thanks Nicos but code won't run. I have been stuck here for over a week. Just paying money without studying. Awkward feeling

Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points
Nikos Tzouvelekis
Nikos Tzouvelekis
8,155 Points

yes sorry i don't realize that it's Kotlin language :) ι just run the challenge and the answer is like just like Steve's answer :) be careful when stuck just read again the exercise :) also you can search at the google etc

Steve Hunter
Steve Hunter
57,712 Points
Steve Hunter
Steve Hunter
57,712 Points

Hi there,

Now we're talking about the right course, I can help you out! You posted in the other thread which wasn't a Kotlin course at all.

Don't delete the import; leave that in. So, here you want to create a string variable called randomNumber. That looks like:

val randomNumber: String = Random();

There's a method called nextInt() in the Random class which generates random numbers with the range passed in as the argument. Use the value 10 for this:

val randomNumber: String = Random().nextInt(10);

But we want to store the value as a string, not a number so chain the .toString() method onto the end:

val randomNumber: String = Random().nextInt(10).toString();

That should get you through the challenge.

Steve.

Enyang Mercy
PLUS
Enyang Mercy
Courses Plus Student 2,339 Points
Enyang Mercy
Enyang Mercy
Courses Plus Student 2,339 Points

Thanks guys. U have truly helped and i apologize for the inconveniences.