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Python SQLAlchemy Basics Introduction to SQLAlchemy Querying the Movie Database

Peter Brandstetter
Peter Brandstetter
7,163 Points

Answer not valid

In task #1 we should search for all movies with genre 'Romance' and store it in a variable. I don't get what's wrong with my query and the compiler/interpreter info isn't really helpful.

My Code:

romance_movies = session.query(Movie).filter(Movie.genre=='Romance')
models.py
from sqlalchemy import create_engine, Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker


engine = create_engine(β€˜sqlite:///movies.db’, echo=False)
Session = sessionmaker(bind=engine)
session = Session()
Base = declarative_base()


class Movie(Base):
    __tablename__ = β€˜movies’

    id = Column(Integer, primary_key=True)
    movie_title = Column(String)
    genre = Column(String)

# Write your code below
romance_movies = session.query(Movie).filter(Movie.genre=='Romance')

1 Answer

Steven Parker
Steven Parker
228,991 Points

There were two other questions with the exact same issue in the past 10 days (one, two)!

As I told them: based on the Regex error shown on the Test Results tab, the challenge apparently doesn't like the "Movie." prefix in the filter expression. You can remove that to pass the challenge, but you might also want to report this as a bug to the Support folks.

Peter Brandstetter
Peter Brandstetter
7,163 Points

Thanks a lot.

Sometimes the regex even donβ€˜t accept valid whitespaces πŸ˜…

Steven Parker
Steven Parker
228,991 Points

The challenge should probably allow anything that would be valid code, that's why I suggested reporting it.