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```Math.floor(Math.random() * (6 - 1 + 1)) + 1;
function randomNumber(top, bottom) {
var randomMath = Math.floor(Math.random() * (top - bottom + 1)) + bottom;

if (parseInt(randomMath) > parseInt(bottom)){

}else {
}
}
randomNumber(100, 20);
``` I would recommend being more careful about how you format your code. You're missing a semi-colon, but it's hard to tell the way you've written it.

Your code works when I try it in the console with a semi-colon after your randomNumber declaration.

```// This line isn't needed, it will execute and not impact your function randomNumber
//Math.floor(Math.random() * (6 - 1 + 1)) + 1;

function randomNumber(top, bottom) {
var randomMath = Math.floor(Math.random() * (top - bottom + 1)) + bottom;
if (parseInt(randomMath) > parseInt(bottom)) {
}else {
}
};

randomNumber(100, 20);
``` It's just a suggestion, I've had plenty of times where a long function will throw an error because of a missing semi-colon or closing brace. Keeping your format spaced out and tidy will really help with syntax errors and higher order functions when you start writing complex logic. I had to learn that the hard way! -Good Luck!

I formatted your code into a code block. Once I did that, I could see that you weren't actually missing a semicolon anywhere!

The reason this doesn't work is because`parseInt` is used to convert a string into an integer. In this case, you can't use it on `randomMath` because that will already be an integer (because `Math.floor()` returns an integer). It also won't do anything if `bottom` is a number, as it would when you call `randomNumber(100, 20)` at the end of your code.

In this challenge you were only meant to output the generated random number so the user could see it. It wasn't meant to be a guessing game.

If you take out the entire conditional statement (`if` ... `else`) and instead just `return randomMath`, then at the end you can use `alert(randomNumber(100, 20));` and you should get the random number between 20 and 100 in a pop-up box.