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Any way to make cleaner code?
It works for the most part, I was having a hard time with displaying an error message if someone entered a name into the number question. i used .isdigit() at first, but i couldn't find a way to have 2 else statements next to each other so I just completely removed it. I started to get a feeling that this wasn't important for where we're at right now in the course. I'm not sure if I followed the directions properly, but it works. Any way to make this code a little cleaner and more concise?
name = input("Please enter your name: ") number = input("Please enter a number: ") true_number = int(number) print(name) print(number) if true_number % 3 == 0 and true_number % 5 == 0: is_fizzbuzz = True print("is a FizzBuzz Number") elif true_number % 3 == 0 and true_number % 5 != 0: is_fizz = True print("is a Fizz Number") elif true_number % 3 != 0 and true_number % 5 == 0: is_buzz = True print("is a Buzz Number") else: print("This is neither a Fizzy or a Buzzy Number")
Any Help is appreciated
Steven Parker210,425 Points
You can directly assign the results of a comparison to a variable, and avoid re-testing conditions previously eliminated by other tests:
is_fizz = true_number % 3 == 0 is_buzz = true_number % 5 == 0 if is_fizz and is_buzz: print("is a FizzBuzz Number") elif is_fizz: print("is a Fizz Number") elif is_buzz: print("is a Buzz Number") else: print("This is neither a Fizzy or a Buzzy Number")