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Alright, last step but it's a big one. Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1. I know it's a lot, but I know you can do it!

even.py
```import random
def even_odd(num):
# If % 2 is 0, the number is even.
# Since 0 is falsey, we have to invert it with not.
return not num % 2
start = 5
while start < 1:
number = even_odd(random.randint(1, 99))
if number = True:
print("{} is even".format(number))
else:
print("{} is odd".format(number))
start = start - 1
```

STAFF

Hi there! In addition to the answer left above, you have some other things going on. Your `number` variable is set to be equal to the result of running `even_odd` on the random number generated. Because of this number will only ever be equal to `True` or `False` and not a number. I would suggest using just the code to generate a random number and assign that random number to the variable `number`.

Furthermore, your `else` will never trigger. In your `if` statement, you a are not doing a comparison to `True` but rather an assignment to `True`. This will always succeed.

Instead, once you fix your while loop so that it begins as stated by Henrik Christensen, you should be doing a comparison on the evaluation of your random number passed into the `even_odd` function there. I would suggest:

```if even_odd(number):
```

Hope this helps!

Have a look at this part while start < 1 it says "WHILE start IS LESS than 1" and since start = 5 IS GREATER than 1 the while-loop will never run.

I hope this helps :-)