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PHP Build a Simple PHP Application Adding a Contact Form Concatentation

Posted by Casey Choi
Casey Choi
540 Points

Anything wrong with these codes below. $fullName = $firstName . "\n" . $midleName . "\n" . $lastName;

Anything wrong with these codes below. I was told to put spaces among those variables, but it doesn't go thru.

$fullName = $firstName . "\n" . $midleName . "\n" . $lastName;

concatenation.php 
<?php
$fullName = $firstName . "\n" . $midleName . "\n" . $lastName;
$lastName = "Frog";
$firstName = "Mike";
$middleName = "the";



echo "The designer at Shirts 4 Mike shirts is named ____";

?>

2 Answers

Ken Alger
STAFF
Ken Alger
Treehouse Teacher
Ken Alger
Ken Alger
Treehouse Teacher

Casey;

Welcome to Treehouse!

You just need spaces, not newline characters. Remove the \n references and you should be good. Also, you need to define the $fullName variable after the other variables. Until then it won't know what $firstName, $middleName, or $lastName are or are equal to. Your $fullName variable assignment would then look like:

$fullName = $firstName . ' ' . $middleName . ' ' . $lastName;

Happy coding,

Ken

Casey Choi
Casey Choi
540 Points

Thank you very much! I love the teamtreehouse!

Rich Bagley
Rich Bagley
25,869 Points
Rich Bagley
Rich Bagley
25,869 Points

Hi Casey,

You have the $fullName variable set before the other 3 which means it won't be able to take their values as they haven't been set yet.

I also noticed you're missing a 'd' from $middleName in the concatenation line.

Your line under the 3 variables would then look something like:

$fullName = $firstName . ' ' . $middleName . ' ' . $lastName;

Hope that helps

-Rich

Casey Choi
Casey Choi
540 Points

Thank you very much!

Rich Bagley
Rich Bagley
25,869 Points

No problem, happy to help :)

-Rich