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iOS Objective-C Basics (Retired) Fundamentals of C Arrays

array code challenge 4/4

I can't see, where's my fault.

char alpha; alpha = 'a';

char bravo;
bravo = 'b';

char letters[2];
letters[0] = alpha;
letters[1] = bravo;

printf("letters a %c\n", letters[1]);

the result should look like "letters a b"

2 Answers

Drop the newline character

already tried same fault given

Amit Bijlani
Amit Bijlani
Treehouse Guest Teacher

You have to pass in 2 arguments to the printf statement: printf("letters %c %c\n", letters[0],letters[1]);