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iOS Objective-C Basics (Retired) Fundamentals of C Arrays

Posted by Tobi Meier
Tobi Meier
1,966 Points

array code challenge 4/4

I can't see, where's my fault.

char alpha; alpha = 'a';

char bravo;
bravo = 'b';

char letters[2];
letters[0] = alpha;
letters[1] = bravo;

printf("letters a %c\n", letters[1]);

the result should look like "letters a b"

2 Answers

John W
John W
21,558 Points
John W
John W
21,558 Points

Drop the newline character

Tobi Meier
Tobi Meier
1,966 Points
Tobi Meier
Tobi Meier
1,966 Points

already tried same fault given

Amit Bijlani
Amit Bijlani
Treehouse Guest Teacher
Amit Bijlani
Amit Bijlani
Treehouse Guest Teacher

You have to pass in 2 arguments to the printf statement: printf("letters %c %c\n", letters[0],letters[1]);