Array intead of range not working

Hi thomas, here's a basic example of what you are after, I can't tell you whats wrong without seeing the code, but here's a quick over view of what I think your trying to do.

//1. Create an array of numbers with a range from I through to 10

let numbers = [1...10];

//2. Create for loop and go through array

for number in numbers {

//3. Print number range

print(number);

}

Hi Sam,

Sorry for not including the code. So here are two examples I suppose I do not declare the array correctly and that is the reason for code not to work. The example that works for me is:

var numbers = 1...100

for number in numbers{ if ((number % 3 == 0 && number % 5 == 0)){ println("Fizz Buzz") } else if (number % 5 == 0){ println("Buzz") } else if (number % 3 == 0){ println("Fizz") } else { println(number) } }

The one that fails is:

var numbers = [1...100]

for number in numbers{ if ((number % 3 == 0 && number % 5 == 0)){ println("Fizz Buzz") } else if (number % 5 == 0){ println("Buzz") } else if (number % 3 == 0){ println("Fizz") } else { println(number) } }

Can I not declare the array like that?:

var numbers = [1...100]

I'm sorry I did not realise it will not format the code.

One of the fundamental principles of Swift is that is does not implicitly convert between types this is why you were getting an error. Stick to the first example you were correct with that.