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sebastian rojas
571 PointsArray to string conversion error
hey! im trying to code some via the videos and im getting an error at line 59
<?php
$products = array();
$products[101] = array(
"name" => "Logo Shirt, Red",
"img" => "img/shirts/shirt-101.jpg",
"price" => 18
);
$products[102] = array(
"name" => "Mike the Frog Shirt, Black",
"img" => "img/shirts/shirt-102.jpg",
"price" => 20
);
$products[103] = array(
"name" => "Mike the Frog Shirt, Blue",
"img" => "img/shirts/shirt-103.jpg",
"price" => 20
);
$products[104] = array(
"name" => "Logo Shirt, Green",
"img" => "img/shirts/shirt-104.jpg",
"price" => 18
);
$products[105] = array(
"name" => "Mike the Frog Shirt, Yellow",
"img" => "img/shirts/shirt-105.jpg",
"price" => 25
);
$products[106] = array(
"name" => "Logo Shirt, Gray",
"img" => "img/shirts/shirt-106.jpg",
"price" => 20
);
$products[107] = array(
"name" => "Logo Shirt, Turquoise",
"img" => "img/shirts/shirt-107.jpg",
"price" => 20
);
$products[108] = array(
"name" => "Logo Shirt, Orange",
"img" => "img/shirts/shirt-108.jpg",
"price" => 25,
);
?><?php
$pageTitle = "Mike's full Catalog of shirts";
$section = "shirts";
include('include/header.php'); ?>
<div class ="section page">
<div class="wrapper">
<h1>Mike’s full catalog of shirts</h1>
<ul>
<?php foreach($products as $product) {?>
<li><?php echo $product; ?></li>
<?php } ?>
</ul>
</div>
</div>
<?php include ('include/footer.php'); ?>
this is where i get my error
<h1>Mike’s full catalog of shirts</h1>
<ul>
<?php foreach($products as $product) {?>
<li><?php echo $product; ?></li>
<?php } ?>
</ul>
Notice: Array to string conversion in C:\xampp\htdocs\COMPTURBO\shirts.php on line 59 Array
2 Answers
Dino Paškvan
Courses Plus Student 44,108 PointsYes, but his $products array contains strings as elements, while your array (the one you've pasted) contains other arrays as elements, so you need to provide an additional key to specify which part of the inner array you want to access/output.
Dino Paškvan
Courses Plus Student 44,108 PointsAh, I see what you mean. Based on the version of PHP it might not be possible to have the $echo construct output Array when you use an array as an argument, so that's what's causing the error. If you try accessing an element via key directly (as in the example I posted), it should work. Or you could pass the array to a function like implode() first, to convert it into a string.
sebastian rojas
571 PointsI tried out the code as you said and it worked! :)
But i had not paid enough notice to the video so i missed the code that he wrote so it all worked out! hehe :)
Dino Paškvan
Courses Plus Student 44,108 PointsThe elements inside the $products array are arrays themselves, so you should specify which element (via key) you want to output:
<?php echo $product["name"]; ?>
sebastian rojas
571 PointsWell, im trying to follow this video http://teamtreehouse.com/library/build-a-simple-php-application/listing-inventory-items/displaying-all-products
and he haven't done a such thing and it is working for him so im abit confused atm :/
Tibor Ruzinyi
17,968 PointsTibor Ruzinyi
17,968 PointsHi , which piece of code did you write wrong ? Iam having the same problem :)