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Luke Dunning
231 PointsArray Variables
Hi, i am having trouble understanding why this is incorrect , and i have tried it multiple ways in xcode and it compiles perfectly to what the question is asking, can anyone see an issue with my code ?
include <stdio.h>
int main() {
char alpha[] = {'a'};
alpha[0] = 'a';
printf("alpha %c\n", alpha[0]);
char bravo[] = {'b'};
alpha[0] = 'b';
printf("bravo %c\n", bravo[0]);
return 0;
}
2 Answers
Taylor Weeks
4,009 PointsYou do not need the square brackets in the variable declaration. A character is not an array.
char alpha = 'a'; char bravo = 'b';
Luke Dunning
231 PointsAhh thank you so much Taylor :)