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iOS Objective-C Basics (Retired) Fundamentals of C Arrays

Luke Dunning
Luke Dunning
231 Points

Array Variables

Hi, i am having trouble understanding why this is incorrect , and i have tried it multiple ways in xcode and it compiles perfectly to what the question is asking, can anyone see an issue with my code ?

include <stdio.h>

int main() {

char alpha[] = {'a'};

alpha[0] = 'a';

printf("alpha %c\n", alpha[0]);

char bravo[] = {'b'};

alpha[0] = 'b';

printf("bravo %c\n", bravo[0]);

return 0;


2 Answers

Taylor Weeks
Taylor Weeks
4,009 Points

You do not need the square brackets in the variable declaration. A character is not an array.

char alpha = 'a'; char bravo = 'b';

Luke Dunning
Luke Dunning
231 Points

Ahh thank you so much Taylor :)