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Front End Web Development Techdegree Student 3,302 PointsArrays
var temperatures = [100,90,99,80,70,65,30,10]; for (var i = 10; i < temperatures.length; i += 1){ console.log(temperatures[0]) }
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 10; i < temperatures.length; i += 1){
console.log(temperatures[0])
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Julian Gutierrez
19,201 PointsYou need to start the loop on the first value in the array which would be temperatures[0], so start by setting the variable i to that. Inside the loop you are logging out temperatures[0] which will continually log out "100" to the console. You need to instead log out every value in the array; since "i" is being incremented after every iteration of the loop you can use temperatures[i] inside of your console.log.
Maxwell DeMers
6,853 PointsYes, should look like this.
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i < temperatures.length; i += 1){
console.log(temperatures[i])
};
This will log 100 90 99 etc.