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JavaScript

Frankie Lamar
Frankie Lamar
11,120 Points
Posted by Frankie Lamar
Frankie Lamar
11,120 Points

Arrays Stage 4 Exercises 2 of 2

I'm trying to sort an sayings2[ ] by string length. For some reason this isn't clicking for me. I've watched the video twice and tried to figure it out on stackoverflow and w3 school without any luck. Can somebody please explain this to me.

<!DOCTYPE html> <html lang="en"> <head> <title> JavaScript Foundations: Arrays</title> <style> html { background: #FAFAFA; font-family: sans-serif; } </style> </head> <body> <h1>JavaScript Foundations</h1> <h2>Arrays: Methods Part 1</h2> <script> var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"]; var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"]; saying1.reverse(); sayings2.sort(function(a,b){ return a.length < b.length});

</script>

</body> </html>

3 Answers

Frankie Lamar
Frankie Lamar
11,120 Points
Frankie Lamar
Frankie Lamar
11,120 Points

copy and pasting that code didn't quite turn out right. Here is the link on code pen: http://cdpn.io/pcAbm

terrymartin
terrymartin
2,343 Points
terrymartin
terrymartin
2,343 Points

Rewatch the 'Return a-b' part, that function as an argument is how you solve it.

a.length & etc.

Drew Botka
Drew Botka
13,315 Points
Drew Botka
Drew Botka
13,315 Points

for one you have an unneeded "s" in your variable name: "sayings2" should be "saying2"

instead of using the < comparison I switched to -

saying2.sort(function(a,b){ return a.length - b.length});