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Python Python Basics Functions and Looping Create a Function

Posted by Khaja Ahmed
Khaja Ahmed
198 Points

AssertionError: 5 != 1 :

squaring.py 
def square (number):
    return number * 5

1 Answer

Steven Parker
Steven Parker
230,274 Points
Steven Parker
Steven Parker
230,274 Points

The message may be a little confusing, but the instructions asked for a function that would square the passed argument, but that's not what this code is doing.

One way to calculate a square would be to multiply the value by itself, but multiplying by 5 would only create a square if the argument was also 5 (and the tester obviously tries other values).

Khaja Ahmed
Khaja Ahmed
198 Points

i still didn't get it i am new to programming.

Steven Parker
Steven Parker
230,274 Points
Steven Parker
Steven Parker
230,274 Points

You can't use "5" because that would only work if the argument was 5. To get a square, you must multiply the number by itself (so instead of "number * 5", you might write "number * number").