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iOS Objective-C Basics (Retired) Pointers and Memory Pointers

Rael Kanushefsky
Rael Kanushefsky
1,041 Points

Assign the variable "pointy" the address of "alpha".

Im struggling to pass the 3rd challenge. 'Assign the variable "pointy" the address of "alpha".'

char *pointy; char alpha = 'k';

??? pointy = &k;

Can anyone help me with why it would pass? Thanks

char *pointy;
char alpha = 'k';
pointy = &k;

1 Answer

Martin Wildfeuer
Martin Wildfeuer
Courses Plus Student 11,071 Points

With your code, you are assigning the address of k to pointy, which does not exist, though. With the code below, pointy points to the address of char alpha, this should pass.

char *pointy;
char alpha = 'k';
pointy = α

Hope that helps :)