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Raedawn Long
6,943 PointsAssistance with passing agruements while calling.
passing arguments
function returnValue (echo) {
var echo
return ('echo');
}
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
4 Answers
Steven Parker
229,644 PointsYou don't need to create a new variable in this function. And you would certainly not want to create one with the same name as a parameter. This causes what is known as "shadowing" and makes the parameter inaccessible.
Also, don't enclose a variable name in quotes. Anything in quotes is treated as a string literal and not a variable.
Raedawn Long
6,943 Pointsyaaayyy!! figured it out! ty again!
Raedawn Long
6,943 PointsHey Steven, can you give me an example on how to start a max function with numbers its my last objective ?
Steven Parker
229,644 PointsA "max" function would take two arguments, perform a test to see which one is larger, and return the larger one.
Raedawn Long
6,943 PointsI thought so, I keep getting error I put ex
function max(width, length) {
}
Steven Parker
229,644 PointsThat's a good start, but now you need the body code to perform the test and returns.
Raedawn Long — We seem to have wandered off the original topic. If the original question has been answered, you can mark it solved by choosing a "best answer".
Happy coding!