At 3:00 why does step[0] and step[1] iterate to next tuple item?

Hey! Thanks for answering, you answered my previous question 5 minutes ago.

You say: "It does not have to do with the size of step". Why doesn't it? I don't see why the outcome isn't just: ['0: a'], ['0: a'], ['0: a'] etc... like my previous problem was. What makes enumerate iterate through the whole list? I'm sorry I don't get it.

Perhaps we are thing of "size" differently. I am thinking that "size" is similar length of the item.

# tuple of length ("size") 2
(0, 'a')
# tuple of length ("size") 4
(0, 1, 2, 3)
# list of length  ("size") 3
['a', 'c', 'e']

In Kenneth's code:

for step in enumerate(my_alphabet_list):
    print("{}: {}".format(*step)

enumerate keeps track of the number of iterations and in each loop, it returns the iteration count and the next item from the iterable, in this case my_alphabet_list.

For the first iteration, enumerate returns (0, a) On the next iteration, it returns (1, b), next it returns (2, c), etc.

On each iteration the tuple returned by enumerate is assigned to the variable step.

The "star" notation *step means to expand step into a it's individual members.

*step is shorthand for step[0], step[1]

Thank you very much. I understand it now.

It's that this example is about simply formatting the output. But the last example was about appending to the variable.