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# Below is the case. I not sure how to pass.

Create a new function named max() which accepts two numbers as arguments. The function should return the larger of the two numbers. You'll need to use a conditional statement to test the 2 numbers to see which is the larger of the two.

function max(2, 5) { if(2 > 5) { console.log(true); } else { console.log(false); } }

script.js
```function max(2, 5) {
if(2 > 5) {
console.log(true);
} else {
console.log(false);
}
}
```

You need to return the larger number, not a true/false. And these need to be named parameters, so:

```function max(a, b) {
if(a > b) {
return a;
} else {
return b;
}
}
```

Thanks

First of all, you need to create the max() function and pass it two arguments. Then compare those arguments with if else . Lastly, alert the max() funtion.

``` function max(a,b){};
```

Compare a and b with if else statement

```if(a>b) { // is a greater than b?
return a;
}

else {
return b;
}
max(10,1)// 10 represents a and 1 is b...  now we pass the arguments to the function once we call it.
```

``` alert(max(10,1)); //you can delete the above the else statement max() function  for the second part.