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Android

Posted by Noel Hwande
Noel Hwande
10,558 Points

Blog Reader project - Opening a Webpage in the Browser - Code Challenge 2/2

I've been stuck on this challenge for a while. I think the hint might be throwing me off. Please help.

@Override
protected void onListItemClick(ListView l, View v, int position, long id) {
  super.onListItemClick(l, v, position, id);
  String url = mUrls.getString();
  Intent intent = new Intent(Intent.ACTION_VIEW);
  intent.setData(Uri.parse(url));
  startActivity(intent);
}

4 Answers

Liam Peters
Liam Peters
8,792 Points

Ok, so basically what is happening is, when you click an item in the list, you want to go to a URL corresponding to that list in your browser. You are given that mUrls is an array (hint hint) of string values. What you're attempting to do is to set the data of the intent to a string version of an array, Not a single URL string. This: String url = mUrls.getString(); needs to be something along the lines of: String url = mUrls[position]; So you are fetching the string value from the array at the correct position! Hope this doesn't confuse you more :S

David Bouchare
David Bouchare
9,224 Points
David Bouchare
David Bouchare
9,224 Points

Hi there,

I am also having the same issues. Here is the code I wrote:

   @Override
protected void onListItemClick(ListView l, View v, int position, long id) {
    // Add code here!
    super.onListItemClick(l, v, position, id);
    String url = mUrls[0];
    Intent intent = new Intent(Intent ACTION_VIEW);
    intent.setData(Uri.parse(url));
    startActivity(intent);
}

But it's obviously not correct. Any ideas?

David Bouchare
David Bouchare
9,224 Points
David Bouchare
David Bouchare
9,224 Points

... Sorry for the spam, I wrote Intent ACTION_VIEW instead of Intent.ACTION_VIEW. It's now working. Thanks for the tip Liam

Noel Hwande
Noel Hwande
10,558 Points
Noel Hwande
Noel Hwande
10,558 Points

Thanks, Liam. That helped. On to the next lesson...