Bottles of beer in Swift

Question

I wanted to write code singing the bottle of beer song. The iteration was easy but I didn't have knowledge of who to count down in stead of iterate up. I found an example online but I'm having issues, it just runs forever with no errors and no results. Here is what I have...

//: Playground - noun: a place where people can play

import UIKit

for i in stride(from: 99, to: 0, by: -1) {
    if i == 99 {
        print("\(i) bottles of beer on the wall, \(i) bottle of beer. You take one down pass it around...")
    } else if i < 99 && i > 1 {
        print("\(i) bottles of beer on the wall")
        print("\(i) bottles of beer on the wall, \(i) bottle of beer. You take one down pass it around...")
    } else if i == 1 {
        print("\(i) bottle of beer on the wall")
        print("\(i) bottle of beer on the wall, \(i) bottle of beer. You take one down pass it around...")
    } else {
        print("We all pass out drunk!")
    }
}

I want the first line, 99, not to have the additional, "Bottle of beer", 98-2, to have the addition, "Bottles of beer", and 1 to only say, "Bottle". I thought I had it perfect but, it's not completing, what am I doing wrong?

Thanks! Happy Swifting.

Answer 1 · 2015-06-22T15:12:59Z

June 22, 2015 3:12pm

Your problem was that the loop stops at zero and never finishes, you need to stop the loop at -1 so it processes the last line. You can reduce the code to just a few lines:

for i in stride(from: 99, to: -1, by: -1) {
    if (i < 99 && i > 0) {
        println("\(i) bottles of beer on the wall.")
    }
    if  (i > 0) {
        println("\(i) bottles of beer on the wall, \(i) bottle of beer. You take one down pass it around...")
    }        
    if i == 0 {
        println("We all pass out drunk!")
    }
}

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Bottles of beer in Swift

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