Stuart McDonald1,474 Points
Bug in echo flavor?
According to my understand, echo "$flavor"; should display the value of $flavor. The only way I can get this to work is echo $flavor; Shouldn't both be correct as they can both display the value of $flavor?
<?php $flavor = 'Chocolate'; echo "<p>Your favorite flavor of ice cream is "; echo "$flavor"; echo ".</p>"; echo "<p>Hal's favorite flavor is cookie dough, also!</p>"; ?>
Henrik ChristensenPython Web Development Techdegree Student 38,298 Points
You should get chocolate when you echo "$flavor"; since it's in double-quotes but there is no point doing it like that in this challenge.
Instead just do it like this:
<?php echo $flavor;