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Java Build a JavaFX Application Graphical User Interfaces Adding an Event Handler

Posted by princess mudyahoto
princess mudyahoto
18,502 Points

build a javaFx application

Challenge Task 1 of 1

Let's build an app that is like an old school boom box. There is a play button, when it is clicked, print out to the console "Playing!"

com/example/Home.java 
package com.example;

import javafx.application.Application;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.stage.Stage;

public class Home extends Application {

    @Override
    public void start(Stage primaryStage) throws Exception{
        Group root = new Group();
        Button playButton = new Button();
        // Add an event handler for playButton

        root.getChildren().add(playButton);
        primaryStage.setTitle("Boombox");
        primaryStage.setScene(new Scene(root, 300, 275));
        primaryStage.show();
    }


    public static void main(String[] args) {
        launch(args);
    }
}

3 Answers

Zach Freitag
Zach Freitag
20,341 Points
Zach Freitag
Zach Freitag
20,341 Points

Spoiler Alert!

package com.example;

import javafx.application.Application;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.stage.Stage;

public class Home extends Application {

    @Override
    public void start(Stage primaryStage) throws Exception{
        Group root = new Group();
        Button playButton = new Button();
        // Add an event handler for playButton
        playButton.setOnAction(evt -> System.out.println("Playing!"));

        root.getChildren().add(playButton);
        primaryStage.setTitle("Boombox");
        primaryStage.setScene(new Scene(root, 300, 275));
        primaryStage.show();
    }


    public static void main(String[] args) {
        launch(args);
    }
}
Duy Pham
PLUS
Duy Pham
Courses Plus Student 44,614 Points
Duy Pham
Duy Pham
Courses Plus Student 44,614 Points

. You have to use the method .setOnAction on the Button and then use lambdas to print out the text. You should watch the section "Adding Interactivity" again. At 3:30, Mr.Craig explained very well about that. .By the way, here is the answer: playButton.setOnAction(evt -> System.out.println("Playing!"));

Stewart Mandla Kohlisa
Stewart Mandla Kohlisa
11,737 Points
Stewart Mandla Kohlisa
Stewart Mandla Kohlisa
11,737 Points

it does need anything special,it only requires one line of code

wic is ...... playButton.setOnAction(evt -> System.out.println("Playing!"));