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my code is

var randomNumber = Math.floor(Math.random() * 6) + 1 ; var guess = prompt("i am thinking the number between 1 and 6 , what it is?") if(parseInt(guess) === randomNumber){ document.write("<h1> You Guess The Right Number </h1>") }else if(!NaN){ document.write("<h1>you have entered the invalid entry " + guess + "</h1>") }else{ document.write("<h1>You Guess the wrong number,the random number was " +randomNumber+ "</h1>") }

I also want to show that suppose if user entered the string so it should show invalid entry . Every time it showing invalid entry even on integer.

Hey Prakhar,

I noticed in what I could gather from your code that you're checking `if (!NaN)`. Your if statements should be almost always comprised of dynamic data. `if (!NaN)` is a static if-statement that will always evaluate to true because you are saying "If NaN is a falsey value, do this code." NaN will always be a falsey value, so the if statement always executes which is why you get the invalid entry message every time an incorrect guess has been made.

```var randomNumber = Math.floor(Math.random() * 6) + 1 ;
var guess = prompt("I am thinking of a number between 1 and 6.  What is it?");
//Added 10 to parseInt so that it will explicitly get the number inside guess from the base 10 system
if(parseInt(guess, 10) === randomNumber){
document.write("You Guessed The Right Number!")
}
//Check to see if guess is not a number
else if (isNaN(guess)) {