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Python Python Basics (2015) Logic in Python Try and Except

Sabas Mejia
Sabas Mejia
378 Points
Posted by Sabas Mejia
Sabas Mejia
378 Points

BUMER !

What's wrong with code ? : (for I tried all possible codes and still says "Try again!" try: num1 = int(input("Give me the 1st number: ")) num2 = int(input("Give me the 2nd number: ")) float(num1) float(num2) except ValueError: print("None") else: print(num1 + num2)

trial.py 
try: 
    num1 = int(input("Give me the 1st number: "))
    num2 = int(input("Give me the 2nd number: "))
    float(num1)
    float(num2)
except ValueError:
    print("None")
else:
    print(num1 + num2)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

Many of the challenges moving forward will not utilize the input and print for input and output. Instead the challenge checker will exercise the code by calling the function with various arguments to test the code.

Items to correct in your code:

  • remove input statements
  • change print statements to return statements
  • convert to float using reassignment, such as: num1 = float(num1)
  • returning nothing is the same as return with no argument

Post back if you still have issues. Good Luck!!