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C# C# Objects Inheritance Throwing Exceptions

Justin Amyx
Justin Amyx
2,280 Points
Posted by Justin Amyx
Justin Amyx
2,280 Points

Bummer: I entered valid value 2 and got an exception. Not sure what is going on here?

Got stuck with try/catch for a bit, then found out I didn't need those. Compiled the value's, checked forums after "throw(exception)" didn't work, fixed the syntax, now I get "Bummer: I entered valid value 2 and got an exception."

NO WHERE here do I see anything that should flag 2. Again to the forums, this exact code has worked for others?

Program.cs 
int value = int.Parse(Console.ReadLine());

    if (value < 0 || value > 20);
      {
        throw new System.Exception();
      }


Console.WriteLine(string.Format("You entered {0}",value));

2 Answers

KRIS NIKOLAISEN
KRIS NIKOLAISEN
54,972 Points

The semicolon terminates this line and should be removed:

if (value < 0 || value > 20);
Justin Amyx
Justin Amyx
2,280 Points
Justin Amyx
Justin Amyx
2,280 Points

Thank you for the help that fixed it.