Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
Noor Hafiza Binti Ibrahim11,616 Points
Bummer: Uh oh, I didn't get the correct value returned. It should have been [5, 6, 7, 9]. Instead, it was 8
# enter your code below def pop(list, index): try: newlist = list.pop(index) return newlist except IndexError as error: return ('Invalid Index')
Chris FreemanTreehouse Moderator 67,514 Points
Hey Noor Hafiza Binti Ibrahim, you are very close!
pop() method operates on a list in-place and returns the popped item. So
newlist will contain the popped item and
list will be the modified list. change to
return list to pass the challenge.
BTW, using the name of a built-in
list as a variable name overrides its definition locally. So
list() would no longer work with the function. Alternative names could be
Post back if you need more help. Good luck!!