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PHP PHP Basics Daily Exercise Program Conditionals

Han Oh
Han Oh
5,284 Points
Posted by Han Oh
Han Oh
5,284 Points

"Bummer: Use the variables to display the message" What does this mean? I tested my code and it works as in "Preview"

"Bummer: Use the variables to display the message" What does this mean? I tested my code and it works as in "Preview"

index.php 
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

if ($studentOneGPA == 4.0) {
  $disp = "$studenOneName made the Honor Roll.";
}
else {
  $disp = "$studentOneName has a GPA of $studentOneGPA";
}

echo $disp;

if ($studentTwoGPA == 4.0) {
  $disp = "$studentTwoName made the Honor Roll.";
}
else {
  $disp = "$studentTwoName has a GPA of $studentTwoGPA";
}
echo $disp;
?>

3 Answers

deebird
deebird
7,558 Points
deebird
deebird
7,558 Points

You need to echo the requested string inside your if statements, using the variables at the top

if($studentOneGPA == 4.0){
    echo $studentOneName . ' made the Honor Roll';
}else{
echo $studentOneName . ' has a GPA of ' . $studentOneGPA;
}

if($studentTwoGPA == 4.0){
    echo $studentTwoName . ' made the Honor Roll';
}else{
echo $studentTwoName . ' has a GPA of ' . $studentTwoGPA;
}
Han Oh
Han Oh
5,284 Points
Han Oh
Han Oh
5,284 Points

Hi deebird, it still gives me the same error. Here's the revised code.

<?php $studentOneName = 'Dave'; $studentOneGPA = 3.8;

$studentTwoName = 'Treasure'; $studentTwoGPA = 4.0;

if ($studentOneGPA == 4.0) { echo $studenOneName . ' made the Honor Roll.'; } else { echo $studentOneName . ' has a GPA of ' . $studentOneGPA; }

if ($studentTwoGPA == 4.0) { echo $studentTwoName . ' made the Honor Roll.'; } else { echo $studentTwoName . ' has a GPA of ' . $studentTwoGPA; } ?>

Han Oh
Han Oh
5,284 Points
Han Oh
Han Oh
5,284 Points

Hi deebird, I found the error. It's my bad... I mistyped $studentOneName in the first if block with $studenOneName.