Bummer! Where's `word_count()`?

Question

I have no idea what is wrong with this. It seems to be working okay.

word_count.py

# E.g. word_count("I am that I am") gets back a dictionary like:
# {'i': 2, 'am': 2, 'that': 1}
# Lowercase the string to make it easier.
# Using .split() on the sentence will give you a list of words.
# In a for loop of that list, you'll have a word that you can
# check for inclusion in the dict (with "if word in dict"-style syntax).
# Or add it to the dict with something like word_dict[word] = 1.

def word_count(string):
  work = string.lower()
  work = work.split()
  a = 0
  work1 = work[:]
  for s in work:
    while s in work1:
      a += 1
      work1.remove(s)
    dic[s]=a
    work1 = work[:]
    a=0
  return dic

Answer 1 · 2016-04-21T02:47:05Z

April 21, 2016 2:47am

I got it to work after I defined 'dic'. Other than adding dic = {}, your code works fine. Nice work.

def word_count(string):
    work = string.lower()
    work = work.split()
    a = 0
    work1 = work[:]
    dic = {}
    for s in work:
        while s in work1:
            a += 1
            work1.remove(s)
        dic[s]=a
        work1 = work[:]
        a=0
    return dic

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cyjung

cyjung

Bummer! Where's `word_count()`?

1 Answer

John Lindsey

John Lindsey

John Lindsey

John Lindsey