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# Call a function with a random number of arguments

I have a function like that:

```def my_function(*args):
for arg in args:
print(arg)
```

and I would like to call it with a random number of arguments. Something like:

```args = tuple(random.randint(1, 500) for _ in range(10))
my_function(args)
```

And I can't make it work. Any suggestions?

Thanks

Jacques MOD

Jacques Plomion, you are correct that `my_function` is seeing the tuple as a single argument. The power of the asterisk in `*args` can be used in two ways:

• as a catchall to receive an arbitrary number of arguments, and
• to expand a container into individual arguments

The second way is used when you see code like:

```    def __init__(*args, **kwargs):  # used here to catch all arguments
super().__init(*args, **kwargs)  # used here to expand back to individual arguments
```

So, the simple solution is to call your function as: `my_function(*args)`

```>>> import random
>>> args = tuple(random.randint(1, 500) for _ in range(10))
>>> args
(284, 481, 276, 323, 22, 1, 274, 395, 425, 381)
>>> my_function(args)
(284, 481, 276, 323, 22, 1, 274, 395, 425, 381)
>>> my_function(*args)
284
481
276
323
22
1
274
395
425
381
```

Post back if you have more questions. Good Luck!!

Thanks Chris. MOD

Hey Jacques,

You need to import the random library:

```import random
```

then you can call:

```random.randint(n1, n2)
```

or

```from random import randint
```

then you can call:

```randint(n1, n2)
```

Hi Clayton,

Thanks for taking the time to respond to me. I guess I didn't explain what I am trying to do well enough so let me try again:

I am trying to call `my_function` with a random number of arguments in *args. The args would be determined randomly when I run the script. So doing:

```args = tuple(random.randint(1, 500) for _ in range(10))
my_function(args)
```

creates a tuple with a random number of arguments and when I call `my_function` I get this result:

```(332, 224, 406, 410, 352, 306, 245, 455, 456, 89)   # for example
```

I think this is because my tuple is seen as one argument (a tuple) when I would like it to be seen as several integer arguments. I hope it is more clear. And again, thank you for helping with this.

Jacques