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JavaScript Object-Oriented JavaScript (2015) Prototypal Inheritance Setting Up the Prototype Chain

calling with "call" method

You're going to modify the Teacher code to inherit from the Person. First, in the Teacher constructor function, call the Person constructor, using the call method and pass in the common attributes. Can anyone tell me what is the right way to call this constructor?

person.js
function Person(firstName, lastName) {
  this.firstName = firstName;
  this.lastName = lastName;
}

Person.prototype.fullName = function() {
 return this.firstName + " " + this.lastName; 
};
teacher.js
function Teacher(firstName, lastName, roomNumber) {
  person.Call(this, firstName, lastName );
  this.firstName = firstName;
  this.lastName = lastName;
  this.room = roomNumber;
}

1 Answer

Gunhoo Yoon
Gunhoo Yoon
5,027 Points

First of all Call() doesn't exist in JavaScript but call() does. JavaScript is case-sensitive and I think that was your main issue.

What call() does is using a function on behalf of other context. It's like borrowing a function.

In this case, Teacher has to have names and room number. Since we defined a constructor that already knows how to build names Teacher just need to be extended from Person. This means Teacher doesn't need to define its own name properties if Teacher extends Person.

You are close

Teacher.js
function Teacher(firstName, lastName, roomNumber) {
  person.call(this, firstName, lastName );
  this.room = roomNumber;
}