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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Mykiel Horn
Mykiel Horn
4,014 Points

Can anyone tell me what is wrong with the else part of my loop?

The challenge keeps telling me that task one isn't passing, which is creating the start variable and assigning 5 to it. When I placed all of my code into the workspace I received a SyntaxError for the line where the else is.

import random

start = 5
def even_odd(num):
  # If % 2 is 0, the number is even.
  # Since 0 is falsey, we have to invert it with not.

  while True:
    ran_num = random.randint(1,99)
    if ran_num % 2 == 0:
      print("{} is even".format(ran_num)
    else:
      print("{} is odd".format(ran_num)
    start -= 1
  return not num % 2

2 Answers

Steven Parker
Steven Parker
229,783 Points
Steven Parker
Steven Parker
229,783 Points

A syntax error invalidates the entire script and causes the re-testing of earlier tasks to fail. Take a closer look at your "print" statements.

Also, you should not modify the provided "even_odd" function for this challenge. The code you write for task 3 should come after the function. But you will find it handy to use the function in creating your code.

Steven Parker
Steven Parker
229,783 Points
Steven Parker
Steven Parker
229,783 Points

Would the downvoters please explain what I might change to make my hints more useful (without leaving explicit spoilers, I don't want to do that).

nakalkucing
nakalkucing
12,964 Points
nakalkucing
nakalkucing
12,964 Points

Hi there! I would suggest taking a look at your parenthesis.