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# Can I count in reverse order with range?

I recall being able to count backwards with range but have not really been able to do so with a couple of blocks I've tried to use. When I pass a -1 as the third arg in range nothing seems to happen. Am I doing something wrong here?

maps.py
```backwards = [
'tac',
'esuoheerT',
'htenneK',
[5, 4, 3, 2, 1],
]

def reverse(arg):
letlist = []
for char in arg:
print(char)
letlist.append(char)
print(letlist)
newword= []
count = len(letlist)
print(count)
for i in range(count, -1):
print(i)
newword.append(letlist[i])
return newword

print(reverse('words'))
```

Instead of `for i in range(count, -1):`, you could try `for i in range(count, 0, -1):` so that `i` will start at the value of `count` and continue until `i` is not greater than 0. This will give you an `IndexError: list index out of range` for its first value of `i`, since `letlist[len(letlist)]` is not valid. Using `range(count - 1, -1, -1)` would solve that issue.
You could simplify your code by returning `args[::-1]`.
`len(letlist)` gives you the number of elements in `letlist`. If `letlist` has 100 elements, then `len(letlist)` would be 100. The first element in `letlist` would be at `letlist[0]` and its last element at `letlist[99]`, which is also `letlist[-1]`. You get an IndexError if you try `letlist[100]` when the length of `letlist` is less than 101.