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Python Introducing Lists Build an Application Multidimensional Musical Groups

Michael Hale
Michael Hale
2,556 Points

Can not finish question. There seems to be an error in the base code somewhere that I can not debug.

I am trying to answer the question but no matter how clean my code is there is an error. Even without my code and just the template alone an error code is thrown. I am not sure what to do. Either I am missing something or there could be an embedded error somewhere.

groups.py
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
Michael Hale
Michael Hale
2,556 Points

The code I put in does not matter. The code wont run as it with just the predefined list. There is a bug somewhere. It fails to run even when all the code is commented out. Here is the code, its works just fine when I plug it into workspace.

musical_groups = [ ["Ad Rock", "MCA", "Mike D."], ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"], ["Salt", "Peppa", "Spinderella"], ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"], ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"], ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"], ["Run", "DMC", "Jam Master Jay"], ] groups = 1 for group in musical_groups: print("{}, ".format(group))

Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

The test will fail if there is no appropriate code to replace the # Your code here.

What code have you tried to use as a reasonable attempt at the solution?

Michael Hale
Michael Hale
2,556 Points

Here is the code

musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
groups = 1
for group in musical_groups:
    print("{}, ".format(group))

This would be the output. As far as I can tell I am doing exactly what the question asks. Out put the groups members separated by a comma.

group
['Ad Rock', 'MCA', 'Mike D.'],
group
['John Lennon', 'Paul McCartney', 'Ringo Starr', 'George Harrison'],
group
['Salt', 'Peppa', 'Spinderella'],
group
['Rivers Cuomo', 'Patrick Wilson', 'Brian Bell', 'Scott Shriner'],
group
['Chuck D.', 'Flavor Flav', 'Professor Griff', 'Khari Winn', 'DJ Lord'],
group
['Axl Rose', 'Slash', 'Duff McKagan', 'Steven Adler'],
group
['Run', 'DMC', 'Jam Master Jay'],

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points

Your answer is not far off. The challenge asks Can you loop through each group and output the members joined together with a ", " comma space as a separator, please?

Your code prints out the group list. Can you add a step to join the list into a string?

Post back if you need more help. Good luck!!!