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After your .sort! call, add an if statement. If rev is true, call reverse! on arr. Keep your numbers array and the puts statement so that you can see your work in action

```def alphabetize(arr, rev=false)
arr.sort!
if rev == true
puts arr.reverse!
end
end

numbers = [1,4,5,6,7,8,55]
alphabetize(numbers)
puts numbers
```

Its telling me this " It looks like your method doesn't default to alphabetizing an array when it doesn't receive a second parameter." You didn't add the else after the if statement.

You want something like this, so it defaults to sorting the array if the 2nd parameter isn't entered (just like it explains):

```def alphabetize(arr, rev=false)
arr.sort!
if rev == true
puts arr.reverse!
else
puts arr
end
end

numbers = ["c", "a", "b"]
alphabetize(numbers)
```

Alternatively, he's a shorter way to do it:

```def alphabetize(arr, rev=false)
arr.sort!
if rev == true then puts arr.reverse! else puts arr end
end

numbers = ["c", "g", "h"]
alphabetize(numbers, true)
``` So i did what you said and this popped up.

"It looks like your method doesn't default to alphabetizing an array when it doesn't receive a second parameter." Okay, so they actually want you to just "return" the answer in the function, not "puts" it. Use this:

```def alphabetize(arr, rev=false)
arr.sort!
if (rev == true)
arr.reverse!
else
arr
end
end

numbers = [1, 2, 7, 3]

puts alphabetize(numbers)
```

Or this shorter version:

```def alphabetize(arr, rev=false)
arr.sort!
if rev == true then arr.reverse! else arr end
end

numbers = ["c", "g", "h"]
puts alphabetize(numbers, true)
```

I did not include the "return" statement in the if/else statements because Ruby automatically returns the last statement, but you could add it if it helps you.

Cheers.