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iOS Swift 2.0 Collections and Control Flow Control Flow With Conditional Statements FizzBuzz

shane reichefeld
PLUS
shane reichefeld
Courses Plus Student 2,232 Points
Posted by shane reichefeld
shane reichefeld
Courses Plus Student 2,232 Points

can someone help me ive gone over this in 3 different ways with 3 different submition questions.....

please help me i cant continue till this works and ive tried and it should have worked the first two ways i did it

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  let ght = [
  n%3 ==0: "Fizz"
  n%5 ==0: "Buzz"
  ]
  for (key, value) in ght {
    switch key{
    case n%3 ==0, n%5 ==0: print("FizzBuzz")
    case n%3 ==0: print("Fizz")
    case n%5 ==0: print("Buzz")


    }

  }
  // End code
  return "\(n)"
}
Jose Patarroyo
Jose Patarroyo
2,953 Points
Jose Patarroyo
Jose Patarroyo
2,953 Points

Hello Shane,

I don't quite remember this challenge, but this is what I see in your code:

I believe you are trying to use a dictionary named ght, it wasn't written properly, you have to use ":" to separate the key from the value; besides, I don't really think you need a dictionary for this task. This function expects a String out as a result, I know you probably don't know yet what I'm talking about (you will soon enough), but the important thing is you are not supposed to use the "print command", instead use return follow by the appropriate string Ex: return "Fizz", or return "Buzz". One last thing, you are using a Switch statement but you are not being exhaustive, meaning that you don't have a default scenario that should be used whenever the expression that is being evaluated doesn't fit any of your cases.

I hope this helps you fix your code, as you know, there are several answers for this challenge, you just have to take into account Passan's steps for this challenge.

1 Answer

Christopher Augg
Christopher Augg
21,223 Points
Christopher Augg
Christopher Augg
21,223 Points

hey Shane,

You will not want to do any loops for this. The function gets one Int value and determines which string it should return (Not print). You will want place something like the following (??? = what should you use?) into the provided code where it says to place it:

if ??? {
        return "FizzBuzz"
    } else if ???  {
        return "Fizz"
    } else if ??? {
        return "Buzz"
    }

Regards,

Chris