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Python Python Collections (2016, retired 2019) Dictionaries Teacher Stats

Posted by Minseok Kim
Minseok Kim
2,708 Points

Can someone help me out with this challenge?

Wow, I just can't stump you! OK, two more to go. I think this one's my favorite, though.

Create a function named most_courses that takes our good ol' teacher dictionary.

most_courses should return the name of the teacher with the most courses. You might need to hold onto some sort of max count variable.

arg = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections']}

def most_courses(arg):
    counter = 0
    for arg.values() in arg.keys():
        if len(arg.values()) >= counter:
            counter = len(arg.values())
        else:
            continue
    if len(arg.values()) in arg.keys() == counter:
        return arg.keys()

I don't know why this doesn't work.

1 Answer

Daniel Medina
Daniel Medina
13,863 Points
Daniel Medina
Daniel Medina
13,863 Points

You have the right idea, but there are a few issues with your code.

The first issue is that you are attaching () in places where they aren't methods. If you type in your function as is into a shell, you'll get

File "<pyshell>", line 3
SyntaxError: can't assign to function call

This is due to your use of arg.values on the third line. What you should have is something more like:

for key, value in arg.items():
    if len(value) > counter:
        counter = len(value)

This allows you to loop through a dictionary using key value pairs. Note that we can simply check if a value is > another rather than using >= in this situation.

You don't really need your else block.

Also, remember that the challenge is asking for the teacher. You'll need to have a string variable for your teacher outside of your for loop. You can re-assign it later based on whatever your counter / maximum count is.

Keep it up, you're almost there!