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Python Python Collections (2016, retired 2019) Dictionaries Word Count

David Agumya
David Agumya
12,285 Points

Can someone help me understand this question. I thought I did but I seem to be missing

Sample Test case I ran on the code:

word_count("I do not like it Sam I Am")

Result: do: 1 like: 1 sam: 1 i: 2 am: 1 it: 1 not: 1

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string_arg):
    str_list = string_arg.split(" ")
    words = string_arg.lower().split(" ")
    dictionary = dict.fromkeys(words, 0)
    for word in str_list:
        word = word.lower()
        dictionary[word] += 1

    return dictionary

1 Answer

Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

To put you on the right track, try:

word_count("I do not like it Sam   I   Am")

The extra white spaces cause unexpected results. Hint: It is in the way you have used split().