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Start your free trialBrian Johnson
Front End Web Development Techdegree Graduate 20,818 PointsCan someone help me with this one?
Please help me!
var request = new XMLHttpRequest();
var xhr = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
xhr.open("GET", "footer.html");
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Steven Parker
231,275 PointsThe challenge has already created the XMLHttpRequest, you don't need to create another one.
Just apply the "open" method to the existing one named "request".
Brian Johnson
Front End Web Development Techdegree Graduate 20,818 PointsThanks Steve!
eslam said
Courses Plus Student 6,734 Pointseslam said
Courses Plus Student 6,734 Points