iOS Functions in Swift Adding Power to Functions Function Parameters

Christopher Roach
Christopher Roach
585 Points
Posted by Christopher Roach
Christopher Roach
585 Points

Can someone please explain the answer to this question for me?

I have no idea why this answer is not working, I've tried the equation in playground and it works correctly.

functions.swift 
// Enter your code below
func getRemainder(value: Int, divisor: Int) -> Int {
    let getRemainderSum = value % divisor

    return getRemainderSum
}

2 Answers

Magnus Hållberg
Magnus Hållberg
16,796 Points
Magnus Hållberg
Magnus Hållberg
16,796 Points

Hi! There is nothing wrong with the code, its just that you have forgotten the internal names "a" and "b". For simplicity you could skip the constant and just return the calculation. 

  return a % b
Christopher Roach
Christopher Roach
585 Points
Christopher Roach
Christopher Roach
585 Points

Hi Magnus,

Thanks for the quick reply. Would you please be able to write out the entire correct function as I seem to try this and it's still not working. I want to figure out where I am going wrong.

Thanks,

Chris

Christopher Roach
Christopher Roach
585 Points
Christopher Roach
Christopher Roach
585 Points

Don't worry, figured it out :)

func getRemainder(value a: Int, divisor b: Int) -> Int { return a % b }