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Start your free trialBlake Handson
1,642 PointsCan someone please explain this code challenge solution ?
Ok, so I think I kind of understand what's going on in this code challenge solution.
Here's what me thinks:
-first the function is defined -a tuple is created to hold values from the iterables -the index and value of iter1 is being matched with the index and value of iter2 and added to the output tuple
Am I getting this completely mixed up ?
Thanks :)
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
##iterables are just a list or something you can iterate through haha
def combo(iter1, iter2):
output = ():
for index, value in enumerate(iter1):
output.append((value, iter2[index]))
return(output)
1 Answer
Steven Parker
231,275 PointsIt think you have the idea but I might state it a bit differently:
The indices are being matched up .. and then the values associated with them in each iterable are being combined into a tuple, which is then appended to your master list of tuples.
Blake Handson
1,642 PointsAwesome, thanks Steven I understand now. Thanks for you reply.
Jason Anello
Courses Plus Student 94,610 PointsJason Anello
Courses Plus Student 94,610 PointsHi Blake,
This code won't pass as it is currently written. You have a few errors where you initialize your
output
variable.output = ():
You have a colon at the end of the line which has to be removed and the output should be a list, not a tuple.
Tuples are immutable which means you can't change them by appending items to it.