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PHP PHP Basics Daily Exercise Program Conditionals

Posted by Wilson Majok Kuol Bol
Wilson Majok Kuol Bol
1,431 Points

Can someone please explain to me this problem?

Check if each student has a GPA of 4.0. If the student has a GPA of 4.0, use the student's name variable to display "NAME made the Honor Roll". If not, use the variable to display "NAME has a GPA of GPA".

I can understand this description!

index.php 
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if($studentOneGPA == 4.0) {
  echo '$studentOneName made the Honor Roll';
}
else {
  echo '$studentOneName has a $studentOne of $studentTwoGPA';
}
?>

4 Answers

Anton Williams
Anton Williams
5,157 Points
Anton Williams
Anton Williams
5,157 Points

Hi,

I think first of all you need to check both students, not just one, this could be done with two if-statements as this is a simple example, but if you needed to do it for more in the future you'd want to change it to a function. But for this example I wouldn't worry about that.

I'm not sure if the challenge wants to check if the GPA is at least 4.0 or exactly 4.0, but it seems more logical to check if it is 4.0 or higher which is what I've done below.

<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;

$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;

//Place your code below this comment
if($studentOneGPA >= 4.0) {
  echo '$studentOneName made the Honor Roll';
}
else {
  echo '$studentOneName has a GPA of $studentOneGPA';
}

if($studentTwoGPA >= 4.0) {
  echo '$studentTwoName made the Honor Roll';
}
else {
  echo '$studentTwoName has a GPA of $studentTwoGPA';
}
?>

Here is an explanation to the question. You need to test both student's GPAs to see if they make 4.0, if they do make 4.0 you echo "StudentName made the Honor Roll", if they do not make 4.0 then you echo "StudentName has a GPA of StudentGPA".

Wilson Majok Kuol Bol
Wilson Majok Kuol Bol
1,431 Points
Wilson Majok Kuol Bol
Wilson Majok Kuol Bol
1,431 Points

Thanks for answer but it doesn't work still.

Anton Williams
Anton Williams
5,157 Points

Ah it's because the quote marks. When you use ' marks the text in between is completely plain text.

'this is plain text'

where as this will echo the variable

"this shows a $variable"
Victor Utama
Victor Utama
6,934 Points
Victor Utama
Victor Utama
6,934 Points

Yeah, i'm having the same issue.

Victor Utama
Victor Utama
6,934 Points
Victor Utama
Victor Utama
6,934 Points

Strangely... it's the formatting.

<?php $studentOneName = 'Dave'; $studentOneGPA = 3.8;

$studentTwoName = 'Treasure'; $studentTwoGPA = 4.0;

//Place your code below this comment if ($studentOneGPA === 4.0) { echo $studentOneName . " made the Honor Roll"; } else { echo $studentOneName . " has a GPA of " . $studentOneGPA; } if ($studentTwoGPA === 4.0) { echo $studentTwoName . " made the Honor Roll"; } else { echo $studentTwoName . " has a GPA of " . $studentTwoGPA; } ?>

Got that from the other thread. I did something similar and it works for me.