Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python

Can someone please help me figure out how does calling another function into a function function work?

def area_circle(radius): return 3.14*(radius**2)

def inside(hight): area_circle(3) if hight > 2: print("awesome") inside(3) area_circle(3)

Having just a hard time getting the idea in my head, can someone please explain it in details. have no clue what I'm doing in this code by the way. Thanks!

2 Answers

This is the correct code:

def area_circle(radius): 
    return 3.14*(radius**2)

def inside(height): 
    print(area_circle(3))
    #returns: 28.26
    if height > 2: print("awesome") 
    return

# Now you can call area_circle function
print(area_circle(3))
#returns: 28.26

print(inside(3))
#returns: awesome

print(inside(area_circle(3)))
#returns: awesome
def area_circle(radius): 
    return 3.14*(radius**2)

# Now you can call area_circle function
print(area_circle(3)) 

In this example first "area_circle" returns the valus (3.14*3*2) = 28.26...Than print(28.26)

Thanks!!