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Java Java Basics Perfecting the Prototype Censoring Words - Using String Equality

Zeeshan Somani
Zeeshan Somani
323 Points
Posted by Zeeshan Somani
Zeeshan Somani
323 Points

Can someone tell me what is wrong with this code? I am trying this in the interactive session but cannot figure it out.

The point of this code is to output "first is equal to second if the contents of the 2 string are the same. Any ideas?

String firstExample = "hello"; if (firstExample.equals (secondExample)) { console.printf ("first is equal to second."); } String secondExample = "hello"; String thirdExample = "HELLO";

1 Answer

Rich Bagley
Rich Bagley
25,869 Points

Hi Zeeshan,

The first part of the challenge should look like this:

// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";

if (firstExample.equals(secondExample)){
  console.printf("first is equal to second");
}

Is this what you meant?

-Rich

Zeeshan Somani
Zeeshan Somani
323 Points
Zeeshan Somani
Zeeshan Somani
323 Points

That is exactly what I wrote. The only difference is the placement. I placed the if statement between the first and second string. I ran a similar program in workshop so the method should work but the interactive question isn't accepting it. Is the placement at fault?

Rich Bagley
Rich Bagley
25,869 Points

Hi Zeeshan,

Yes you will need to make sure your condition appears after the strings that are set. Think of it as though they can't be compared if they don't exist yet :)

Hope that helps.

-Rich

Zeeshan Somani
Zeeshan Somani
323 Points
Zeeshan Somani
Zeeshan Somani
323 Points

Perfect. Works now. Thanks.

Rich Bagley
Rich Bagley
25,869 Points

No problem :)

-Rich

Aamir Mirza
Aamir Mirza
25,077 Points
Aamir Mirza
Aamir Mirza
25,077 Points

Thanks Rich! I was having trouble with this too. I had the exact same code as you except I put System.exit(0); at the end of the if block. Hopefully that's a bug x_x