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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops The Refactor Challenge, Part 2

can this code work? rgbColor = 'rgb(' + randomRBG() + ',' +randomRBG() + ',' + randomRBG() + ')';

this is the full code.

var html = '';

var rgbColor;


function randomRBG(){ 
 return   Math.floor(Math.random() * 256 );

}


for(var circle = 0;circle < 10 ; circle 
   +=1){

rgbColor = 'rgb(' + randomRBG() + ',' +randomRBG() + ',' + randomRBG() + ')';

html += '<div style="background-color:' + rgbColor + '"></div>';





}

document.write(html);

2 Answers

Steven Parker
Steven Parker
229,582 Points

There's nothing wrong with this code, but it's not complete if you want it to display something on the page.

To make the results visible, you'd need at least some CSS code to go with it, to give the div elements size and shape so they can be seen.

Rahul Saini
Rahul Saini
4,611 Points

```function randomRBG(){ return Math.floor(Math.random() * 256 ); instead of just writing to document use this. document.getElementsByTagName("body").innerHTML = html

Steven Parker
Steven Parker
229,582 Points

Multiplying random by 256 does give you a range from 0 to 255. The random value approaches 1 but never reaches it.