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Python Introducing Lists Build an Application Multidimensional Musical Groups

Efe Mirkan Guner
Efe Mirkan Guner
2,413 Points

can you help me for this code please

i can not complete it

musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],

for list in musical_groups:

abc= ", ".join(list)

2 Answers

14,241 Points

You're overcomplicating stuff. Since musical_groups is a two-dimension object, get hold of each list in the second dimension by creating a for loop targeting the second dimension and printing each item of each list.

Taking your solution into account;

list_number=1 👈# Why?
for list in musical_groups:👈#Here you're targeting the first dimension not the second. Since musical_groups is a list of 
                             #lists specify the inner dimension of the musical_groups which is musical_groups[0] here 0 
                             #is the first list within musical_groups.

abc= ", ".join(list)

So let me give you a template:

for x in musical_groups[]: 👈#Since there are 7 lists within musical_groups' list, use index to target all of them.
    print(", ".join(x))