Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Introducing Lists Build an Application Multidimensional Musical Groups

Can you loop through each group and output the members joined together with a ", " comma space as a separator, please?

Please help. My latest attempt is attached.

musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
group = 1
for group_members in musical_groups:
    group_members = ", ".join(musical_groups)
    print("Group {}: {}".format(musical_groups, group_members))
    group += 1
# Your code here

1 Answer

Steven Parker
Steven Parker
228,094 Points

You're got the right idea, but you want to join the "group_members" instead of the "musical_groups:".

And you can just print that out directly, you don't need any fancy formatting. You also don't need to keep a count.

Got it! Thanks!!