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Python Introducing Lists Build an Application Multidimensional Musical Groups

Posted by Evan Henking
Evan Henking
1,235 Points

Can you loop through each group and output the members joined together with a ", " comma space as a separator, please?

Please help. My latest attempt is attached.

groups.py 
musical_groups = [
    ["Ad Rock", "MCA", "Mike D."],
    ["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
    ["Salt", "Peppa", "Spinderella"],
    ["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
    ["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
    ["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
    ["Run", "DMC", "Jam Master Jay"],
]
group = 1
for group_members in musical_groups:
    group_members = ", ".join(musical_groups)
    print("Group {}: {}".format(musical_groups, group_members))
    group += 1
# Your code here

1 Answer

Steven Parker
Steven Parker
228,094 Points
Steven Parker
Steven Parker
228,094 Points

You're got the right idea, but you want to join the "group_members" instead of the "musical_groups:".

And you can just print that out directly, you don't need any fancy formatting. You also don't need to keep a count.

Evan Henking
Evan Henking
1,235 Points

Got it! Thanks!!