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Evan Henking
1,235 PointsCan you loop through each group and output the members joined together with a ", " comma space as a separator, please?
Please help. My latest attempt is attached.
musical_groups = [
["Ad Rock", "MCA", "Mike D."],
["John Lennon", "Paul McCartney", "Ringo Starr", "George Harrison"],
["Salt", "Peppa", "Spinderella"],
["Rivers Cuomo", "Patrick Wilson", "Brian Bell", "Scott Shriner"],
["Chuck D.", "Flavor Flav", "Professor Griff", "Khari Winn", "DJ Lord"],
["Axl Rose", "Slash", "Duff McKagan", "Steven Adler"],
["Run", "DMC", "Jam Master Jay"],
]
group = 1
for group_members in musical_groups:
group_members = ", ".join(musical_groups)
print("Group {}: {}".format(musical_groups, group_members))
group += 1
# Your code here
1 Answer

Steven Parker
216,165 PointsYou're got the right idea, but you want to join the "group_members" instead of the "musical_groups:".
And you can just print that out directly, you don't need any fancy formatting. You also don't need to keep a count.
Evan Henking
1,235 PointsEvan Henking
1,235 PointsGot it! Thanks!!